Aretiree receives $5120 a year interest from $40,000 placed in two bonds, one paying 14% and the other 12%. how much is invested in each bond? 3)

Investment in first bond is $ 16,000

In second bond is $ 24,000

Step-by-step explanation:

Let x be the amount invested in first bond,

Since, the total invested amount = $ 40,000,

So, the total amount invested in second bond = ( 40,000 - x ) dollars,

Given,

In first bond,

Interest rate = 14%,

While in second bond,

Interest rate = 12%,

Thus, the total interest from both bonds in a year,

I = 14% of x + 12% of ( 40,000 - x )

According to the question,

I = $ 5120,

Hence, the amount invested in first bond = $ 16,000,

The amount invested in second bond = $ 40,000 - $ 16,000 = $ 24,000

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

answer: you need the equation in the question so i can answer it

step-by-step explanation: