How many solutions are there to the equation x1 +x2 +x3 +x4 +x5 = 18, where x1, x2, x3, x4, x5 are non-negative integers, given the follow restrictions: four of the variables must be odd, and the remaining variable (which may be odd or even) yield a remainder of 2 when divided by 3? justify your answer.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation:

well what did you do it matters what you did : )

step-by-step explanation: