Mathematics, 19.07.2019 07:10 brutalgitaffe

The unicorns: stardust, umo, windthorn and highflyer are enjoying themselves playing in the forest. they noticed 8 spiders in the trees, 5 cockroaches, 7 bees, 3 deer, 4 cows and a pair of antlers behind a brush. how many legs do all the numbered creatures amount to altogether?
my opinions
170
162
188
156

The unicorns: stardust, umo, windthorn and highflyer are enjoying themselves playing in the forest.

Answers: 3

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Answers

Answer from: mydoggy152

There are altogether $\fbox{\begin{minispace}\\188 \text{legs}\\\end{minispace}}$ .

Further explanation:

Given:

The number of Unicorns is four: Stardust, Umo, WIndthorn and Highflyer.

The number of Spiders in the tree is five.

The number of cockroaches is five.

The number of bees is seven.

The number of deer is three.

The number of cows is 4.

The number of antlers is 2.

To calculate:

The total number of legs of all the creatures.

Calculations:

It can be seen that the number of legs of a unicorn is 4.

Since, there are four unicorns, it means that the number of legs of unicorns $n _{1}$ can be calculated as,

$n_{1}= 4 \times 4 \\ \fbox{\begin{minispace} \\ n_{1} = 16 \end{minispace}}$

Also, the number of legs of a spider is 8.

Therefore, the number of legs $n_{2}$ of eight spiders can be calculated as,

$n_{2}= 8 \times 8 \\ \fbox{\begin{minispace} \\ n_{2} = 64 \end{minispace}}$

Now, the number of legs of a cockroach is 6, it means that the number of legs $n_{3}$ of five cockroaches can be calculated as,

$n_{3}= 6 \times 5\\ \fbox{\begin{minispace} \\ n_{3} = 30 \end{minispace}}$

Also, the number of legs of a bee is 6, therefore the number of legs $n_{4}$ of seven bees can be calculated as,

$n_{4}= 6 \times 7\\ \fbox{\begin{minispace} \\ n_{4} = 42 \end{minispace}}$

The number of legs of a deer is 4 which lead to the number of legs $n_{5}$ of three deers as,

$n_{5}= 4 \times 3\\ \fbox{\begin{minispace}\\ n_{5} = 12 \end{minispace}}$

The number of legs of a cow is 4 that means the number of legs $n_{6}$ of four cows can be calculated as,

$n_{6}= 4 \times 4\\ \fbox{\begin{minispace} \\ n_{6} = 16 \end{minispace}}$

Also, since it can be seen that a pair of antlers is seen, so it means that the animal seems to be two deers.

Now, a deer has 4 legs, it means that the number of legs $n_{7}$ of two deer is,

$n_{7}= 4 \times 2\\ \fbox{\begin{minispace} \\ n_{7} = 8 \end{minispace}}$

Therefore, the total number of legs can be obtained by adding the values of $n_{1}, n_{2}, n_{3} , n_{4} , n_{5}, n_{6} \text{ and } n_{7}$ .

$n=n_{1}+n_{2}+n_{3}+n_{4}+n_{5}+n_{6}+n_{7}\\ n=16+64+30+42+12+16+8 \\ \fbox{\begin{minispace} \\ n = 188 \end{minispace}}$

Therefore, the total number of legs altogether are 188.

Learn more:

1. Problem on counting.

2. Problem on addition and simplification.

3. what is the y-intercept of the quadratic function f(x) = (x – 6)(x – 2)? (0,–6) (0,12) (–8,0) (2,0)?

Answer details:

Grade: Junior School

Subject: Mathematics

Chapter: Counting

Keywords: addition, multiplication, unicorns, cow, bees, spider, deer, counting, legs, altogether, antlers, cockroaches, playing, forests, stardust, umo, windthorn, highfller, creatures, bush.

The unicorns: stardust, umo, windthorn and highflyer are enjoying themselves playing in the forest.

Answer from: Quest

false

step-by-step explanation:

false. two legs of the trapezoid would be congruent, but the other two would not. were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

Answer from: Quest

60%

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