30 and brainliest asap
what is an equation of the line that is perpendicular to 3x+y=−5 and passes through the point (3, −7) ?
enter your equation in the box.

y = 1/3x -8

Step-by-step explanation:

3x+y=−5

First we need to get the equation in slope intercept form to find the slope

Subtract 3x from each side

3x-3x+y=-3x−5

y = -3x-5

The slope is -3

We want a line perpendicular.  Perpendicualr lines have slopes that are the negative reciprocal.  Take the negative reciprocal

m new = - (1/-3) = 1/3

The slope of the new line is 1/3

We have the slope (1/3) and a point (3,-7)

We can use the point slope form for the equation of a line

y-y1 = m(x-x1)

y--7 = 1/3 (x-3)

y+7 = 1/3 (x-3)

or if we want the slope intercept form

Distribute

y+7 = 1/3x -1

Subtract 7 from each side

y+7-7 = 1/3x -1-7

y = 1/3x -8

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^