Which of the following equations matches the function shown above?

C=y=sin1/2x

Step-by-step explanation:

As given in the graph:

Amplitude= 1

period=2π

Finding function of sin that have period of 4π and amplitude 1

A: y=1/2sinx

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1/2

b=1

c=0

d=0

Amplitude=|a|

                =1/2

Period= 2π/b

         =2π

B: y=sin2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/2

         =π

C: y=sin1/2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/2

         =4π

D: y=sin1/4x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/4

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/4

         =8π

Hence only c: y=sin1/2x has period of 2π and amplitude 1

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7