If you decrease the distance between two celestial objects by a factor of 2.5, how does the resultant gravitational force between the two objects compare to the original force? the force is times stronger.
only enter your numerical answer below 0 do not include units. report your answer to 2 decimal places.

 The force is 6.25 times stronger.

Step-by-step explanation:

The formula to find the force of attraction between any two object is given by :-

                                (i)

, where M and m are the masses of the objects , d is the distance between them and G is gravitational constant.

If you decrease the distance between two celestial objects by a factor of 2.5, then , the new distance will become

Plug this in the above formula , we get

Hence, the force is 6.25 times stronger.

step-by-step explanation:

just plug in each number for x and see which ones work and don't

by definition, an arc subtended by a central angle of some given measure has the same measure. so .