The fibonacci numbers are defined by the recursive formula t1 = 0, t2 = 1, tn - 1 + tn - 2 , where n ∈ n and n > 2. what are the first 9 fibonacci numbers?
a) 0, 1, 1, 2, 3, 5, 8, 13, 21
b) 0, 1, 2, 3, 4, 7, 11, 18, 29
d) 0, 1, 2, 3, 6, 9, 15, 24, 39
(don't worry about c)

Basically fibonachi is
the 1st term+term before first term=2nd term
3rd term=1st term+2nd term
4th term=2nd term+3rd term
etc

starting with t1=0 and t2=1
0,1
add them to get next
0+1=1
 now we have
0,1,1
1+1=2
now we have
0,1,1,2
1+2=3
now we have
0,1,1,2,3
2+3=5
now we have
0,1,1,2,3,5
3+5=8
now we have
0,1,1,2,3,5,8
5+8=13
now we have
0,1,1,2,3,5,8,13
8+13=21
now we have
0,1,1,2,3,5,8,13,21

answer is A

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.