Asap
which equations have no real solution but have two complex solutions?
3x^2-5x=-8 2x^2=6x-5 12x=9x^2+4 -x^2-10x=34

First option:  

Second option:

Fourth option:

Step-by-step explanation:

Rewrite each equation in the form and then use the Discriminant formula for each equation. This is:

1) For :

Then:

Since this equation has no real solutions, but has two complex solutions.

2) For :

Then:

Since this equation has no real solutions, but has two complex solutions.

3) For :

Then:

Since this equation has one real solution.

4) For :

Then:

Since , this equation has no real solutions, but has two complex solutions.

yes

step-by-step explanation:

f is the midpoint of