Afootball quarterback enjoys practicing his long passes
over 40 yards. he misses the first pass 40% of the time.
when he misses on the first pass, he misses the second
pass 20% of the time. what is the probability of missing
two passes in a row?

The probability of missing two passes in a row = 0.08

Step-by-step explanation:

According to the statement it is noticed that the passes missed twice.

Thus,

Football player misses the first chance = Event X

P(X)= 40% = 0.4

Football player misses the second chance = Event Y

P(Y) = 20% = 0.2

The probability of occurring these two events can be calculated by the formula:

P(E)= P(X) * P(Y)

P(E)= 0.4 * 0.2

P(E)= 0.08

Thus the probability of missing two passes in a row = 0.08

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

60

step-by-step explanation:

every triangle measures a total of 120 degrees. you have to find angle c. we know that isosceles triangles angles are equal. 60 degrees plus 60 degrees gives you 120.