Box a contained 1.67 kg of flour. box b contained 8600 g of flour. after same amount of
flour was added to each box, box b contained 4 times as much flour as box a. how
much flour was added to each box? give your answer in kg.

The amount of flour added to each box was 0.64 kg

Step-by-step explanation:

Let

x > the amount of flour added to each box in kg

Remember that

1 kg=1,000 g

8,600 g=8,600/1,000=8.6 kg

we know that

The linear equation that represent this situation is

(8.6+x)=4(1.67+x)

Solve for x

8.6+x=6.68+4x

4x-x=8.6-6.68

3x=1.92

x=0.64 kg

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6