Which is equivalent to (9y^2-4x)(9y^2+4x), and what type of special product is it?
a: 81y^4-16x^2, a perfect square trinomial
b: 81y^4-16x^2, the difference of squares
c: 81y^4-72xy^2-16x^2, a perfect square trinomial
d: 81y^4-72xy^2-16x^2, the difference of squares

Option B: 81y^4-16x^2, the difference of squares

Step-by-step explanation:

we know that

The Difference of Squares is two terms that are squared and separated by a subtraction sign

so

In this problem we have

Let

so

substitute

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.