The vertex form of the equation of a parabola is y=(x-3)^2+35 what is the standard form of the equation

x^2 -6x+44

Step-by-step explanation:

Develop form of (x-3)^2 is x^2 - 6x +9

Then y= x^2 -6x +9 + 35

So, y= X^2 -6x +44

Step-by-step explanation:

The standard form of a quadratic equation is:

.

In this case we have the following quadratic equation in vertex form

Now we must rewrite the equation in the standard form.

Apply the distributive property

the standard form of the equation is:

answer: im gonna go with milli

step-by-step explanation: