The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. the data (in kilometers) follow. find a 99% confidence interval on the difference in the mean life. car brand 1 brand 2 1 37132 34715 2 43879 41479 3 36240 35500 4 32100 31950 5 37210 38015 6 48360 47800 7 38200 37810 8 33500 33215

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%

1/6 of a chance i would believe