How would i compute f(5)+f(2) and the rest

f(5)+f(2)=-18

f(5-2)=-7

f(5)-f(2)=-12

f(5)*f(2)=45

step-by-step explanation:

i just did the ones you got incorrect. let me know if you want me to show you the others too.

1st problem:

we are given f(x)=-4x+5.

to find f(5), we must replace old input x with new input 5, like so -4(5)+5.

f(5)=-4(5)+5

f(5)=-20+5

f(5)=-15

to find f(2), we must replace old input x with new input 2, like so -4(2)+5.

f(2)=-4(2)+5

f(2)=-8+5

f(2)=-3

you are asked to find f(5)+f(2).

f(5) is the same thing as saying -15 here.

f(2) is the same thing as saying -3 here.

f(5)+f(2)

-15+(-3)

-18

so f(5)+f(2)=-18

2nd problem:

f(5-2)

f(3)   sine 5-2=3

now to find f(3), we need to replace old input x with new input 3.

f(3)=-4(3)+5

f(3)=-12+5

f(3)=-7

3rd problem:

f(5)-f(2)

neat thing is we already found f(5) and f(2) in problem 1.

so this problem is equivalent to doing:

-)

-15+3

-12

4th problem:

f(5)*f(2)

we already found f(5) and f(2) in problem 1.

so this problem is equivalent to doing:

-15(-3)

45

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5