Susan is 3 times as old as paul and paul is 3/2 times as old as mary. what fraction of susan's age is mary?
a) 3/8 b) 2/9 c) 15/4 d) 6 e) 13/2

2/9

Step-by-step explanation:

We are given Susan (S) is 3 times as old as Paul (P) so S=3P.

And Paul (P) is 3/2 times as old as Mary (M) so P=(3/2)M.

What fraction of Susan's age is Mary?

So if S=3P and P=(3/2)M, then by substitution we have

Multiply both sides by the reciprocal of 9/2 resulting in:

This says Mary is two-ninths the age of Susan.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

answer: it's d

step-by-step explanation: