Use the substitution method to solve the system of equations. choose the
correct ordered pair.
2x + 3y = 11
y = x - 3
a. (3,0)
b. (5,2)
c. (1,3)
d. (4,1)

D

Step-by-step explanation:

Given the 2 equations

2x + 3y = 11 → I(1)

y = x - 3 → (2)

Substitute y = x - 3 into (1)

2x + 3(x - 3) = 11 ← distribute parenthesis and simplify left side

2x + 3x - 9 = 11

5x - 9 = 11 ( add 9 to both sides )

5x = 20 ( divide both sides by 5 )

x = 4

Substitute x = 4 into (2) for corresponding value of y

y = 4 - 3 = 1

Solution is (4, 1 ) → D

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

i dont know sorry

step-by-step explanation: