Triangle bac was dilated from triangle bde at a scale factor of 2. what proportion proves that tan∠d = tan∠a? triangles bde and bac, in which angle b is a right angle, point d is between points b and a, and point e is between points b and c; bd measures 2 units, be measures 3 units, and de measures 3 and 61 hundredths units. 2 over 3 and 61 hundredths = 4 over 7 and 22 hundredths three halves = six fourths 3 over 3 and 61 hundredths = 6 over 7 and 22 hundredths two thirds = four sixths

three halves = six fourths

Step-by-step explanation:

 tanD = BE/BD = ³/₂

 tanA = BC/BA = ⁶/₄

     ³/₂ = ⁶/₄

∴ tanD = tanA

three halves = six fourths

Step-by-step explanation:

Given that

Then:

Tangent of an angle is computed as follows:

tan(angle) = opposite side/adjacent side

Then:

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

answer: its the third option.

step-by-step explanation:

i just took the test.