Decide whether each of the following statements is true. if false, demonstrate why.
a. 6! = 6.5!
b. 4! + 2! = 6!
c. 6! /3! =2!

a is the only true one if you meant 6 times 5!

Step-by-step explanation:

Before we being

n!=n*(n-1)*(n-2)*...(3)(2)(1)

Example: 5!=5(4)(3)(2)(1) and 10!=10(9)(8)(7)(6)(5)(4)(3)(2)(1)

Yes that operation is multiplication.

a) Does 6!=6*5!

Let's see

6!=6*5*4*3*2*1

5!=5*4*3*2*1

So 6*5!=6(5*4*3*2*1)=6*5*4*3*2*1=6!

So true!

b) Does 4!+2!=6! ?

4!=4(3)(2)(1)

2!=2(1)

6!=6(5)(4)(3)(2)(1)

Does

4(3)(2)(1)+2(1)=6(5)(4)(3)(2)(1)

24          +2  =720

26=720 (this is not true)

So 4!+2! is not 6!

c) Does 6!/3!=2! ?

6!=6(5)(4)(3)(2)(1)

3!=3(2)(1)

If you divide 6! by 3!, then the factors 3 and 2 and 1 cancel and you are left with 6(5)(4).

So the question becomes is 6(5)(4)=2!

2!=2(1)=2

6(5)(4)=2?

No way! That is saying 120=2 which is not true.

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