In the pendulum formula, we use g=9.8 m/s^2 for the acceleration due to gravity on earth. but what about on venus? if an astronaut on the surface of venus swings a 1-meter long pendulum, and it has a period of 2.11 seconds, what is the acceleration due to gravity, g, on venus?

8.9 (just got it on Apex)

Step-by-step explanation:

(guessed correct on Apex due to other questions on that were relative to this one)

Option A is the correct answer.

Step-by-step explanation:

Period of simple pendulum is given by the expression,

Where l is the length of pendulum, g is acceleration due to gravity.

Here given for Venus

         Period, T = 2.11 s

        Length of pendulum, l = 1 m

     We need to find acceleration due to gravity, g

Substituting

Acceleration due to gravity of Venus = 8.9 m/s²

Option A is the correct answer.

it should be a and d. lmk if i'm wrong xd

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)