The number n = 100 + 100^2 + 100^3 + + 100^n . find the least possible value of n such that the number n is divisible by 11. need quickly! !

  n = 11

Step-by-step explanation:

100 mod 11 = 1, which is the remainder from division by 11 for each of the terms of the sum. 11 terms of the sum are needed in order to make the remainders add up to a number divisible by 11.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

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btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )