1a)
use modular arithmetic and congruence to find the last digit of 4362^4362.
1b)
find all solutions to the following linear congruences. justify how many solutions exist.
(a) 2x ≅ 7 (mod 15)
(b) 3x ≅ 6 (mod 15)
(c) 5x ≅1 (mod 15)

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

i have no idea just need points sorry

step-by-step explanation:

its a, i had the same answer, its from study island right

step-by-step explanation: