If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
a. -6
b. square root of -5
c. 6 - square root of 5
d. 6 + square root of 5

-

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

For example, for the equation:

If we take the square root of both sides, the answers will be:

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and . Therefore, the 3rd root of the polynomial function f(x) had to be -

It seems you made error while writing option B, it should be - square root of 5.

21

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584