Find the 8th term in the expansion (x^2 - 9)^9.

-172,186,884x^4.

Step-by-step explanation:

The (r + 1)th term of (a + b)^n = nCr a^(n-r) b^r.

So the 8th term of (x^2 - 9)^9 =

(7 + 1)th term

= 9C7 (x^2)^(9-7) (-9)^7

=  36 * (x^2)^2 * -4782969

= -172186884x^4.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl