What is the coefficient of x^3 in the expansion of (2x-3)^5?
a) -5
b) 10
c) -120
d) -360
e) 720

309

Step-by-step explanation:

(2x-)^5

step 1

1 5 10 10 5 1

step 2

1(2x¹-3^0) 5(2x²-3^5) 10(2x³-3^4)

10(2x^4-3³) 5(2x^5-3²)

1(2x^0-3¹)

step 3

(2x) (10x²-243) (20x³-81) (20x^4-27)

(10x^5-9) (2-3)

step 4

2 -243-61-7 +1 -1=309

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w