Aright triangle has side lengths 7, 24, and 25 as shown below.
use these lengths to find tan b, sin b, and cos b.
tan b
sinb =
lnb
cosb =

see below in bold.

step-by-step explanation:

7 and 24 are the lengths of the 2 legs   and 25 is the length of the hypotenuse.

assuming   angle b is opposite the leg of length 7:

tan b = opposite/ adjacent side = 7/24.

sin b = opposite / hypotenuse = 7/25

cos b = adjacent /hypotenuse = 24/25.

i believe that the answer is

b. y-1=-2(x-4)

hope this !

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2