Consider a particle that moves through the force field f(x, y) = (y − x)i + xyj from the point (0, 0) to the point (0, 1) along the curve x = kt(1 − t), y = t. find the value of k such that the work done by the force field is 1.

The work done by is

where is the given curve and is the given parameterization of . We have

Then the work done by is

In order for the work to be 1, we need to have .

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3