Complete the square for the following quadratic equation to determine its solutions and the location of its extreme value
y = -x + 4x + 12
a
x=2 + 277
extreme value at (2.16)
b.
x = -2,6
extreme value at (2,12)
c.
x = -2.6
extreme value at (2.16)
d. x = 2 + 277
extreme value at (2,12)

Option C. x = -2,6  extreme value at (2.16)

Step-by-step explanation:

we have

This is the equation of a vertical parabola open down

The vertex is a maximum (extreme value)

Convert the equation into vertex form

Complete the square

Group terms that contain the same variable and move the constant term to the left side

Factor -1

Remember to balance the equation by adding the same constants to each side.

Rewrite as perfect squares

-----> equation of the parabola in vertex form

The vertex is the point (2,16) ----> is a maximum (extreme value)

Determine the solutions of the quadratic equation

For y=0

square root both sides

therefore

The solutions are x=-2 and x=6

The extreme value is (2,16)

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.