Simplify the expression. use the varbiables, numbers, and symbols that are shown. drag them to the appropriate box in the polynomial. use standard polynomial format. x(2x+3)+(x-3)(x-4)

  3x² -4x +12

Step-by-step explanation:

This involves straightforward application of the distributive property

x(2x+3)+(x-3)(x-4)

= 2x² +3x +x(x -4) -3(x -4)

= 2x² +3x +x² -4x -3x +12

= 3x² -4x +12

f(x) = 3x^2 - 4x + 12

Step-by-step explanation:

First, let's label the expression and do a little housekeeping:

X(2x+3)+(x-3)(x-4) should be f(x) = x(2x+3)+(x-3)(x-4).

If we perform the indicated multiplication, we get:

f(x) = 2x^2 + 3x + (x^2 - 7x + 12), or

f(x) = 2x^2 + 3x + x^2 - 7x + 12.  Combine like terms to obtain:

f(x) = 3x^2 - 4x + 12

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )