The mean of six numbers is 41. if one number is removed, the mean of the five numbers is 46. find the unknown number.

Mean of 6 numbers is 41  means
(x+y+z+t+a+b)/6=41
(x+5morenumbers)/6=41

if 1 is removed (say x)
mean iof 5 numbers is 46
(5morenumbers)/5=46

multiply first equaiton by 6 and second eqiaton by 5 to clear fractions
x+5morenumbers=246
5morenumbers=230

sub 230 for 5morenumbers in first equaiton
x+230=246
minus 230 both sides
x=16

the unknown is 16

Ab=dc ac=de ad=bce i hope this !