[25 points] with proportions, i don't understand! 134 out of 205 families in "chimgan" village keep cows, 142 keep sheep and 76 keep goats. 67 families have cows and sheep, 10 have cows and goats, 15 have sheep and goats. there are 34 families who keep all three kinds of pets. a) how many families keep only one kind of pet?
b) how many have no pets at all? hint: use the following diagram.

only keeps-

cows=134-67-34-10=23

sheep=142-67-34-15=26

goats=76-10-34-15=17

no pets=205-23-17-26-67-10-16-34

Step-by-step explanation:

some have one pets some have two or three

total no. of family have cows is 134 then 134 minus by those with more will be no. of family only with cows

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square