The ideal gas law states that the volume, v, of a gas in liters varies directly with the amount of the gas in moles, n, and the absolute temperature in kelvin, t, and varies inversely with the pressure, p, of the gas. two moles of a gas has a volume of 35.424 l at 270 kelvin when p = 1.25 atm. what is the volume of 3 moles of a gas at 280 kelvin when p = 1.5 atm?

a.11.48 l
b.27.33 l
c.45.92 l
d.103.32 l

c. 45.92 L

Step-by-step explanation:

According to the given statement, the volume(v) varies directly with number of moles(n), absolute temperature in kelvin(T) and varies inversely with the pressure(P). So we can set up this expression as:

Introducing a proportionality constant(R) we can write  set up the equation as:

                           Equation 1

First we need to find out the value of the proportionality constant before using the equation to find the unknown value of v.

Case 1:

For n = 2, v = 35.424, T = 270 and P = 1.25

Using these values in above equation, we get:

Using this value in Equation 1, we get:

                     Equation 2

Case 2:

Now, we have to find volume for  n=3, T = 280 and P = 1.5

Substituting the values in Equation 2 we get:

Thus, the volume of the gas will be 45.92 L