Adam must fly home to city a from a business meeting in city b. one flight option flies directly to city a from b, a distance of about 456.2 miles. a second flight option flies first to city c and then connects to a. the bearing from b to c is n29.1degreese, and the bearing from b to a is n60degreese. the bearing from a to b is s60degreesw, and the bearing from a to c is n78.3degreesw. how many more frequent flyer miles will adam receive if he takes the connecting flight rather than the direct flight?

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

for future students the answer is b

hope i

-lavira: )

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube