Let z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (round your answers to four decimal places.) (a) p(0 ≤ z ≤ 2.38) .4913 (b) p(0 ≤ z ≤ 1) .3413 (c) p(−2.70 ≤ z ≤ 0) .4965 (d) p(−2.70 ≤ z ≤ 2.70) .9931 (e) p(z ≤ 1.62) .9474 (f) p(−1.55 ≤ z) .9394 (g) p(−1.70 ≤ z ≤ 2.00) .9327 (h) p(1.62 ≤ z ≤ 2.50) .0464 (i) p(1.70 ≤ z) .0445 (j) p(|z| ≤ 2.50) .9876

A standard normal distribution refers to a normal distribution with a mean of 0 and a standard deviation of 1. To solve this proble we're going to need the help of a calculator:

(a) P(0 ≤ Z ≤ 2.38) = 0.4913

(b) P(0 ≤ Z ≤ 1) = 0.3413

(c) P(−2.70 ≤ Z ≤ 0) = 0.4965

(d) P(−2.70 ≤ Z ≤ 2.70) = 0.9931

(e) P(Z ≤ 1.62) = 0.9474

(f) P(−1.55 ≤ Z)= 0.9394

(g) P(−1.70 ≤ Z ≤ 2.00) = 0.9327

(h) P(1.62 ≤ Z ≤ 2.50) = 0.0464

(i) P(1.70 ≤ Z) = 0.0445

(j) P(|Z| ≤ 2.50) = 0.9876

All values are verified! ✅

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong