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determine the number of solutions for the quadratic function f(x) = 3x^2 + 5x + 10.

0 real solutions

Step-by-step explanation:

I guess you are looking for the number of real solutions? Correct me if I'm wrong.

There is something called the discriminant that can help us determine this without actually solving f(x)=0 for x.

The discriminant is the thing inside the square root in the quadratic formula.

It is the thing that reads b^2-4ac.

If b^2-4ac:

A) is negative, then you have 0 real solutions (you could say 2 complex solutions)

B) is positive, then you have 2 real solutions

C) is 0, then you have 1 real solution

So comparing 3x^2+5x+10 to ax^2+bx+c, you should see that a=3, b=5, and c=10.

b^2-4ac

=5^2-4(3)(10)

=25-120

=-95

That is a negative result so you have no real solutions.

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

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