Write a point slope equation for the line that passes through the point (1,22) & is parallel to the line given by y= 14x-3.

y-22=14(x-1)

Step-by-step explanation:

Since we are looking for a line parallel to y=14x-3 then we are looking for a line that has the same slope as y=14x-3.

The slope of y=14x-3 is 14.

So the slope of our line is 14.

So we know our equation is in the form y=14x+b.

We can find b by using a point (x,y) on the line. We know (x,y)=(1,22) is a point on the line we are looking for.

So I'm going to replace x with 1 and y with 22 in the equation y=14x+b giving me

22=14(1)+b

22=14   +b  

Subtract 14 on both sides

8=b

The equation of the line is y=14x+8. That is slope-intercept form.  I will leave this here just in case you are curious of this.

I was do point-slope form now since that is what your question says.

We know the slope is 14 so m=14.

The point-slope form is y-y1=m(x-x1).

We know (x1,y1)=(1,22) so now we substitute.

y-22=14(x-1)

32

step-by-step explanation:

unless if u could do my questions, if not i wouldn't want to