Arectangular storage container with an open top is to have a volume of 10 cubic meters. the length of its base is twice the width. material for the base costs $10 per square meter. material for the sides costs $6 per square meter. find the cost of materials for the cheapest such container. be sure to justify that the cost you find is the cheapest cost for this container

163.54$

Step-by-step explanation:

Given data

Volume of Storage(V)=

Length=2breadth

Let Length be L,Breadth be & height be H

therefore

10=LBH

Now substitutes the values

10=2

5=

Now cost for base is

Cost for side walls is

Now total cost(C)=

C=20++

C=20+24BH+

C=

Now Differentiating With respect to Breadth to get minimum cost

and mimimum cost C

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

17.08

correct me if i am wrong.