You need 320 ml of a 65% alcohol solution. on hand, you have a 60% alcohol mixture. how much of the 60% alcohol mixture and pure alcohol will you need to obtain the desired solution?
you will need
ml of the 60% solution
and
ml of pure alcohol.

You will need

280 mL of the 60% solution

and  40 mL of pure alcohol.

Step-by-step explanation:

Let 'x' be the amount of 60% alcohol solution and y the amount of pure alcohol.

Therefore:

(0.6x + y)/320 = 0.65 ⇒ 0.6x + y = 208

x + y = 320

Solving the sistem of equations:

x = 280 and y = 40

Therefore, You will need

280 mL of the 60% solution

and  40 mL of pure alcohol.

b.

step-by-step explanation:

1) letter c.

2) 4 square root of 9

hope this

step-by-step explanation: