Apiggy bank contains some dimes and nickels. there are 8 more dimes than nickels in the bank. there is a total of $1.40. how many of each type of coin are in the bank?

This question is solved using a system of equations. I am going to say that:

Doing this, we get that: There are 4 nickels and 12 dimes.

There are 8 more dimes than nickels in the bank.

This means that:

There is a total of $1.40.

Thus, for the nickels:

Since

For the dimes:

There are 4 nickels and 12 dimes.

A similar question is found at link

4 nickels

12 dimes

Step-by-step explanation:

Dimes are worth .1 each while nickels are .05 each.

We have 8 more dimes than nickels. Let d represent number of dimes and n for number of nickels. This means we have d=8+n.

If all our nickels and dimes together are worth 1.4 then we have another equation .1d+.05n=1.4

Lets put our equations together:

d=8+n

.1d+.05n=1.4

‐Plug first equation into second.

.1(8+n)+.05n=1.4

Distribute

.8+.1n+.05n=1.4

Combine like terms

.8+.15n=1.4

Subtract .8 on both sides

.15n=.6

Divide both sides by .15

n=.6/.15=4

Remember there are 8 more dimes so d=8+4=12.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.