If there are x teams in a sports league, and all the teams play each other twice, a total of n(x) games are played, where n(x)equalsxsquaredminusx. a football league has 7 teams, each of which play the others twice. if the league pays $45 per game, how much will it cost to play the entire schedule?

$1,890

Step-by-step explanation:

Without including repeated instances of games (for instance, if I said that team 4 plays team 2 twice, then that would just be repeating when I already said that team 2 plays team 4 twice):

Team 1 plays:

teams 2, 3, 4, 5, 6, and 7 twice for a total of 12 games

Team 2 plays:

teams 3, 4, 5, 6, and 7 twice for a total of 10 games

Team 3 plays:

teams 4, 5, 6, and 7 twice for a total of 8 games

Team 4 plays:

teams 5, 6, and 7 twice for a total of 6 games

Team 5 plays:

teams 6 and 7 twice for a total of 4 games

Team 6 plays:

team 7 twice for a total of 2 games

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Total it up:

Multiply by cost per game.

all teachers

step-by-step explanation:

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.