Aball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t) = 52t - 16t^2 . what is the maximum height that the ball will reach?
do not round your answe

42.25 feet

Step-by-step explanation:

The height function is a parabola.  The maximum value of a negative parabola is at the vertex, which can be found with:

x = -b/2a

where a and b are the coefficients in y = ax² + bx + c.

Here, we have y = -16t² + 52t.  So a = -16 and b = 52.  The vertex is at:

t = -52 / (2×-16)

t = 13/8

Evaluating the function:

h(13/8) = -16(13/8)² + 52(13/8)

h(13/8) = -169/4 + 169/2

h(13/8) = 169/4

h(13/8) = 42.25

a

step-by-step explanation:

answer: 5100 just subtract

step-by-step explanation: