Using the discriminant, how many solutions and what type of solution(s) does k^2-10k+25=0 have?
a. 2; irrational
b. 2; rational
c. 1; rational
d. no real solutions

c. 1; rational

Step-by-step explanation:

k² − 10k + 25 = 0

The discriminant of ax² + bx + c is b² − 4ac.

If the discriminant is negative, there are no real roots.

If the discriminant is zero, there is 1 real root.

If the discriminant is positive, there are 2 real roots.

If the discriminant is a perfect square, the root(s) are rational.

If the discriminant isn't a perfect square, the root(s) are irrational.

Finding the discriminant:

a = 1, b = -10, c = 25

(-10)² − 4(1)(25) = 0

The discriminant is zero, so there is 1 rational root.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

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