"the average starting salary of individuals with a master's degree in statistics is normally distributed with a mean of $48,000 and a standard deviation of $6,000. what is the probability that a randomly selected individual with a master's in statistics will get a starting salary of at least $55,000?

12.1%

Step-by-step explanation:

First calculate the z-score:

z = (x − μ) / σ

z = (55000 − 48000) / 6000

z = 1.17

Look up in a z-score table.

P(z>1.17) = 1 − 0.8790

P(z>1.17) = 0.1210

There's a 12.1% probability that a randomly selected individual with a master's in statistics will have a starting salary of at least $55,000.

answer:

sometimes

*i think

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: