The length of a rectangle is 5 centimeters less than twice its width. it’s area is 28 square centimeters. find the dimensions of the rectangle

It didn't saying anything about rounding but the the dimensions in there exact form are:

and

.

Now if they said to round to the nearest hundredths the dimensions in this rounded form would be:

L=5.39 cm and W=5.19 cm

(Check your question again and see if you meant what you have)

Step-by-step explanation:

L is 5 less than twice W

L = 2W-5

Area of rectangle=L*W

Area is 28 means L*W=28.

I'm going to insert L=2W-5 into L*W=28 giving me

(2W-5)*W=28

Distribute

2W^2-5W=28

Subtract 28 on both sides

2W^2-5W-28=0

a=2

b=-5

c=-28

We are going to use the quadratic formula.

Plug in...

W needs to be positive so

And

Does L*W=28?

Let's check.

In the last step, I was able to do a quick multiplication because I was multiplying conjugates.  (a+b)(a-b)=a^2-b^2.

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w