Let v be a vector space and let w be a. nonempty subset of v. then w is a subspace of v if and only if the following conditions hold (a) if u and v are in w, then uv is in w. (b) if u is in w and c is a scalar, then cu is in w. use the theorem above to determine whether w is a subspace of v. v f, w (fin f : f(-x) = -f(x)} w is a subspace of v w is not a subspace of v.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

honesty mood

step-by-step explanation:

according to egenuity the answer is

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d. 344.22

c

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