(10 points) write the given second order equation as its equivalent system of first order equations u"2.5u-2.5u = -5.5 sin(3t) u'(1)-3.5 u(1) = -5, use u to represent the "velocity function", i. e. v = u'(t). and u for the two functions, rather than u(t) and v(t). (the latter confuses webwork. functions like sin(t) are ok.) use now write the system using matrices: u u dt v and the initial value for the vector valued function is: u(1) v(1)

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

answer: what is the question you're trying to ask?

step-by-step explanation: