What is the solution set of the quadratic inequality x^2-5=< 0

{x|√5 ≥ x ≥ -√5}

Step-by-step explanation:

Simply take the ±√5 then square it to get rid of the radical [5].

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Step-by-step

x^2-5<=0 (1)

can be rewritten as

x^2<=5  (2)

which gives the solution set

|x| <=sqrt(5)   (3)

(3) can be rewritten as

x<=sqrt(5), and -x <=sqrt(5) which gives a solution set of

x<=sqrt(5) and x>=-sqrt(5) (4)

The combined conditions of (4) can be rewritten as

-sqrt(5) <= x <= +sqrt(5)

which can also be rewritten in interval notation

[-sqrt(5), sqrt(5)]

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

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