Brianna went to a carnival. she played five games and rode six rides. justin went to the same carnival and played seven games and rode eight rides. if brianna paid $11.75 and justin paid $16.15, how much did one game cost to play?
$0.50
$1.45
$1.25
$1.50
urgent!

  $1.45

Step-by-step explanation:

To answer the question, we would like to have an equation that has the cost of a game as its only variable. That is, we would like to eliminate the cost of a ride from the system of equations we must write.

Let g and r represents the costs of a game and a ride, respectively. Then the expenses of the two carnival-goers can be described by ...

  5g +6r = 11.75

  7g +8r = 16.15

We note that the ratio of coefficients in the variable (r) that we want to eliminate is 3:4. So we can subtract 4 times the first equation from 3 times the second to eliminate that variable.

  3(7g +8r) -4(5g +6r) = 3(16.15) -4(11.75)

  g = 1.45 . . . . . . simplify

The cost to play one game was $1.45.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x