Which statement correctly compares ab and fd?
ab and fd are the same length.
ab is longer than fd.
o
ab is shorter than fd
ab is shorter than or the same length as fd.

AB is longer than FD.

Step-by-step explanation:

This is an SAS triangle problem.

According to the law of cosines,

c^2 = a^2 + b^2 - 2abcosC

In triangle ABC, a = BC, b = AC, and c = AB

In triangle FDE, a = DE, b = FE, and c = FD.

The only difference is that C is 72° in one triangle and 65° in the other.

We know that cos0° = 1 and cos 90° = 0, so cos72° < cos65°.

In triangle ABC, cosC is smaller, so you are subtracting a smaller number from a^2 + b^2.

c^2 is larger, so c is larger.

AB is longer than FD.

That makes sense because, as you widen the angle between your outstretched arms, the distance between your hands increases.

it is probably the graph on the bottom right.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: