Solve (x-3)^2/3=9 (the ^ is an exponent)

Step-by-step explanation:

Step-by-step explanation:

To answer the question you have t the square of the differences.

So this means that (x-3)^2= x^2-9x+9

Next youmultiply 3 on both sides which says…

x^2-9x+9=27

x^2-9x=18

So, x equals

9/2+3/2 square root 17

OR

9/2-3/2 square root 17

answer:

what is your question that you ask

step-by-step explanation:

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!