−5x+4y=38 −x+2y=10 solve by elimination

(-6, 2)

Step-by-step explanation:

-5x + 4y - 38 = 0 (1) | -x +2y - 10 = 0 (2)

First i multiply the 2nd equation by -5, because i want the magnitude of the x coefficient to be the same but with opposite signs, because when i'll add the equations the x's are going to cancel.

(2) * (-5):

5x - 10y + 50 = 0 (2')

(1) + (2'):

-5x + 4y - 38 + 5x - 10y + 50 = 0

-6y + 12 = 0

y = 2

Use the second equation, before multiplying to find the x - solution.

-x + 2(2) - 10 = 0

-x + 4 - 10 = 0 | add 'x'  to both sides

x = -6

answer: idk

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.